असमीका \(\frac{7-2x}{3}\le \frac{x+1}{6}\) को हल कीजिए।
Solve the inequality \(\frac{7-2x}{3}\le \frac{x+1}{6}\).
Explanation opens after your attempt
Correct Answer
D. \(x\ge \frac{13}{5}\)
Concept
Multiplying by (6) gives \(14-4x\le x+1\), hence \(x\ge \frac{13}{5}\). Moving the variable to the right can sometimes simplify the work.
Why this answer is correct
The correct answer is D. \(x\ge \frac{13}{5}\). Multiplying by (6) gives \(14-4x\le x+1\), hence \(x\ge \frac{13}{5}\). Moving the variable to the right can sometimes simplify the work.
Exam Tip
हर (6) से गुणा करने पर \(14-4x\le x+1\), इसलिए \(x\ge \frac{13}{5}\)। परीक्षा में चर को दाईं तरफ ले जाना कभी-कभी आसान होता है।
Login to save your score, XP, coins and progress.