प्रथम चतुर्थांश में \(x+3y\le 12\) से बने त्रिभुज का (y)-अवरोध कौन-सा है?
In the first quadrant, what is the (y)-intercept of the triangle formed by \(x+3y\le 12\)?
Explanation opens after your attempt
B. ((0,4))
Concept
Putting (x=0) gives (3y=12), so (y=4). Hence the vertex on the (y)-axis is ((0,4)).
Why this answer is correct
The correct answer is B. ((0,4)). Putting (x=0) gives (3y=12), so (y=4). Hence the vertex on the (y)-axis is ((0,4)).
Exam Tip
(x=0) रखने पर (3y=12) इसलिए (y=4)। इसलिए (y)-अक्ष पर शीर्ष ((0,4)) है।
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