यदि \(U=\mathbb{R}\) और \(A={x:x \in \mathbb{R}, x^2 \ge 9}\), तो (A') क्या है?

If \(U=\mathbb{R}\) and \(A={x:x \in \mathbb{R}, x^2 \ge 9}\), what is (A')?

Explanation opens after your attempt
Correct Answer

A. ((-3,3))

Step 1

Concept

\(x^2 \ge 9\) means \(x \le -3\) or \(x \ge 3\). Its complement is (-3<x<3), that is ((-3,3)).

Step 2

Why this answer is correct

The correct answer is A. ((-3,3)). \(x^2 \ge 9\) means \(x \le -3\) or \(x \ge 3\). Its complement is (-3<x<3), that is ((-3,3)).

Step 3

Exam Tip

\(x^2 \ge 9\) का अर्थ \(x \le -3\) या \(x \ge 3\) है। इसका पूरक (-3<x<3) यानी ((-3,3)) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U=\mathbb{R}\) और \(A={x:x \in \mathbb{R}, x^2 \ge 9}\), तो (A') क्या है? / If \(U=\mathbb{R}\) and \(A={x:x \in \mathbb{R}, x^2 \ge 9}\), what is (A')?

Correct Answer: A. ((-3,3)). Explanation: \(x^2 \ge 9\) का अर्थ \(x \le -3\) या \(x \ge 3\) है। इसका पूरक (-3<x<3) यानी ((-3,3)) है। / \(x^2 \ge 9\) means \(x \le -3\) or \(x \ge 3\). Its complement is (-3<x<3), that is ((-3,3)).

Which concept should I revise for this Mathematics MCQ?

\(x^2 \ge 9\) means \(x \le -3\) or \(x \ge 3\). Its complement is (-3<x<3), that is ((-3,3)).

What exam hint can help solve this Mathematics question?

\(x^2 \ge 9\) का अर्थ \(x \le -3\) या \(x \ge 3\) है। इसका पूरक (-3<x<3) यानी ((-3,3)) है।