यदि \(U=\mathbb{R}\) और \(A={x:x \in \mathbb{R}, x^2 \ge 9}\), तो (A') क्या है?
If \(U=\mathbb{R}\) and \(A={x:x \in \mathbb{R}, x^2 \ge 9}\), what is (A')?
Explanation opens after your attempt
A. ((-3,3))
Concept
\(x^2 \ge 9\) means \(x \le -3\) or \(x \ge 3\). Its complement is (-3<x<3), that is ((-3,3)).
Why this answer is correct
The correct answer is A. ((-3,3)). \(x^2 \ge 9\) means \(x \le -3\) or \(x \ge 3\). Its complement is (-3<x<3), that is ((-3,3)).
Exam Tip
\(x^2 \ge 9\) का अर्थ \(x \le -3\) या \(x \ge 3\) है। इसका पूरक (-3<x<3) यानी ((-3,3)) है।
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