यदि \(U=\mathbb{R}\) और \(A=\{x:|x-3|<5\}\), तो (A') क्या है?
If \(U=\mathbb{R}\) and \(A=\{x:|x-3|<5\}\), what is (A')?
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-2]\cup[8,\infty\))
Concept
\(|x-3|<5\Rightarrow -2<x<8\), so the complement has \(x\le -2\) or \(x\ge 8\). The complement of a strict inequality includes equality.
Why this answer is correct
The correct answer is A. (\(-\infty,-2]\cup[8,\infty\)). \(|x-3|<5\Rightarrow -2<x<8\), so the complement has \(x\le -2\) or \(x\ge 8\). The complement of a strict inequality includes equality.
Exam Tip
\(|x-3|<5\Rightarrow -2<x<8\), इसलिए पूरक में \(x\le -2\) या \(x\ge 8\) होगा। सख्त असमानता का पूरक बराबरी जोड़ता है।
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