यदि \(U=\mathbb{R}\) और \(A={x:x^2+x-6\ge 0}\), तो (A') क्या है?
If \(U=\mathbb{R}\) and \(A={x:x^2+x-6\ge 0}\), what is (A')?
Explanation opens after your attempt
Correct Answer
A. ((-3,2))
Concept
\(x^2+x-6\ge 0\Rightarrow x\le -3\) or \(x\ge 2\). Its complement is (-3<x<2), that is ((-3,2)).
Why this answer is correct
The correct answer is A. ((-3,2)). \(x^2+x-6\ge 0\Rightarrow x\le -3\) or \(x\ge 2\). Its complement is (-3<x<2), that is ((-3,2)).
Exam Tip
\(x^2+x-6\ge 0\Rightarrow x\le -3\) या \(x\ge 2\)। इसका पूरक (-3<x<2), यानी ((-3,2)) है।
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