\(यदि (U=\mathbb{R}) और (A={x:-3\le x<4\) या \(7<x\le 10}), तो (A') क्या होगा\)?

\(If (U=\mathbb{R}) and (A={x:-3\le x<4\) or \(7<x\le 10}), what is (A')\)?

Explanation opens after your attempt
Correct Answer

A. (\(-\infty,-3\)\cup[4,7]\cup\(10,\infty\))

Step 1

Concept

(A) includes (-3) and (10), but excludes (4) and (7). Therefore the complement is (\(-\infty,-3\)\cup[4,7]\cup\(10,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. (\(-\infty,-3\)\cup[4,7]\cup\(10,\infty\)). (A) includes (-3) and (10), but excludes (4) and (7). Therefore the complement is (\(-\infty,-3\)\cup[4,7]\cup\(10,\infty\)).

Step 3

Exam Tip

(A) में (-3) और (10) शामिल हैं, पर (4) और (7) शामिल नहीं हैं। इसलिए पूरक (\(-\infty,-3\)\cup[4,7]\cup\(10,\infty\)) है।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (U=\mathbb{R}) और (A={x:-3\le x<4\) या 7<x\le 10}), तो (A') क्या होगा? \(/ If (U=\mathbb{R}) and (A={x:-3\le x<4\) or \(7<x\le 10}), what is (A')\)?

Correct Answer: A. (\(-\infty,-3\)\cup[4,7]\cup\(10,\infty\)). Explanation: (A) में (-3) और (10) शामिल हैं, पर (4) और (7) शामिल नहीं हैं। इसलिए पूरक (\(-\infty,-3\)\cup[4,7]\cup\(10,\infty\)) है। / (A) includes (-3) and (10), but excludes (4) and (7). Therefore the complement is (\(-\infty,-3\)\cup[4,7]\cup\(10,\infty\)).

Which concept should I revise for this Mathematics MCQ?

(A) includes (-3) and (10), but excludes (4) and (7). Therefore the complement is (\(-\infty,-3\)\cup[4,7]\cup\(10,\infty\)).

What exam hint can help solve this Mathematics question?

(A) में (-3) और (10) शामिल हैं, पर (4) और (7) शामिल नहीं हैं। इसलिए पूरक (\(-\infty,-3\)\cup[4,7]\cup\(10,\infty\)) है।