यदि \(U=\mathbb{R}\) और \(A={x:-2<x\le 6}\), तो (A') क्या होगा?

If \(U=\mathbb{R}\) and \(A={x:-2<x\le 6}\), what is (A')?

Explanation opens after your attempt
Correct Answer

A. \((-\infty,-2]\cup\(6,\infty\))

Step 1

Concept

(A) does not include (-2) but includes (6), so the complement includes (-2) but excludes (6). The correct answer is ((-\infty,-2]\cup\(6,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. \((-\infty,-2]\cup\(6,\infty\)). (A) does not include (-2) but includes (6), so the complement includes (-2) but excludes (6). The correct answer is ((-\infty,-2]\cup\(6,\infty\)).

Step 3

Exam Tip

(A) में (-2) शामिल नहीं और (6) शामिल है, इसलिए पूरक में (-2) आएगा पर (6) नहीं आएगा। सही उत्तर ((-\infty,-2]\cup\(6,\infty\)) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(U=\mathbb{R}\) और \(A={x:-2<x\le 6}\), तो (A') क्या होगा? / If \(U=\mathbb{R}\) and \(A={x:-2<x\le 6}\), what is (A')?

Correct Answer: A. \((-\infty,-2]\cup\(6,\infty\)). Explanation: (A) में (-2) शामिल नहीं और (6) शामिल है, इसलिए पूरक में (-2) आएगा पर (6) नहीं आएगा। सही उत्तर ((-\infty,-2]\cup\(6,\infty\)) है। / (A) does not include (-2) but includes (6), so the complement includes (-2) but excludes (6). The correct answer is ((-\infty,-2]\cup\(6,\infty\)).

Which concept should I revise for this Mathematics MCQ?

(A) does not include (-2) but includes (6), so the complement includes (-2) but excludes (6). The correct answer is ((-\infty,-2]\cup\(6,\infty\)).

What exam hint can help solve this Mathematics question?

(A) में (-2) शामिल नहीं और (6) शामिल है, इसलिए पूरक में (-2) आएगा पर (6) नहीं आएगा। सही उत्तर ((-\infty,-2]\cup\(6,\infty\)) है।