यदि \(U=\mathbb{R}\), \(A={x:x^2-1\ge 0}\), तो (A') क्या होगा?
If \(U=\mathbb{R}\), \(A={x:x^2-1\ge 0}\), what is (A')?
Explanation opens after your attempt
Correct Answer
A. \((-1,1))
Concept
The solution of \(x^2-1\ge 0\) is \(x\le -1\) or \(x\ge 1\). Its complement is (-1<x<1), that is ((-1,1)).
Why this answer is correct
The correct answer is A. \((-1,1)). The solution of \(x^2-1\ge 0\) is \(x\le -1\) or \(x\ge 1\). Its complement is (-1<x<1), that is ((-1,1)).
Exam Tip
\(x^2-1\ge 0\) का हल \(x\le -1\) या \(x\ge 1\) है। इसका पूरक (-1<x<1), यानी ((-1,1)) है।
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