\(यदि (U=\mathbb{R}), (A={x:-5\le x<-1\) या \(2<x\le 7}), तो (A') क्या है\)?

\(If (U=\mathbb{R}), (A={x:-5\le x<-1\) or \(2<x\le 7}), what is (A')\)?

Explanation opens after your attempt
Correct Answer

A. (\(-\infty,-5\)\cup[-1,2]\cup\(7,\infty\))

Step 1

Concept

(-5) and (7) are in (A), while (-1) and (2) are not in (A). Therefore the complement is (\(-\infty,-5\)\cup[-1,2]\cup\(7,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. (\(-\infty,-5\)\cup[-1,2]\cup\(7,\infty\)). (-5) and (7) are in (A), while (-1) and (2) are not in (A). Therefore the complement is (\(-\infty,-5\)\cup[-1,2]\cup\(7,\infty\)).

Step 3

Exam Tip

(-5) और (7) (A) में हैं, जबकि (-1) और (2) (A) में नहीं हैं। इसलिए पूरक (\(-\infty,-5\)\cup[-1,2]\cup\(7,\infty\)) है।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (U=\mathbb{R}), (A={x:-5\le x<-1\) या 2<x\le 7}), तो (A') क्या है? \(/ If (U=\mathbb{R}), (A={x:-5\le x<-1\) or \(2<x\le 7}), what is (A')\)?

Correct Answer: A. (\(-\infty,-5\)\cup[-1,2]\cup\(7,\infty\)). Explanation: (-5) और (7) (A) में हैं, जबकि (-1) और (2) (A) में नहीं हैं। इसलिए पूरक (\(-\infty,-5\)\cup[-1,2]\cup\(7,\infty\)) है। / (-5) and (7) are in (A), while (-1) and (2) are not in (A). Therefore the complement is (\(-\infty,-5\)\cup[-1,2]\cup\(7,\infty\)).

Which concept should I revise for this Mathematics MCQ?

(-5) and (7) are in (A), while (-1) and (2) are not in (A). Therefore the complement is (\(-\infty,-5\)\cup[-1,2]\cup\(7,\infty\)).

What exam hint can help solve this Mathematics question?

(-5) और (7) (A) में हैं, जबकि (-1) और (2) (A) में नहीं हैं। इसलिए पूरक (\(-\infty,-5\)\cup[-1,2]\cup\(7,\infty\)) है।