यदि \(U=\mathbb{R}\), (A=\(-\infty,-1\)\cup[3,8)), तो (A') क्या है?
If \(U=\mathbb{R}\), (A=\(-\infty,-1\)\cup[3,8)), what is (A')?
Explanation opens after your attempt
Correct Answer
A. ([-1,3)\cup[8,\infty))
Concept
(-1) is not in (A), (3) is in (A), and (8) is not in (A). Hence the complement is ([-1,3)\cup[8,\infty)).
Why this answer is correct
The correct answer is A. ([-1,3)\cup[8,\infty)). (-1) is not in (A), (3) is in (A), and (8) is not in (A). Hence the complement is ([-1,3)\cup[8,\infty)).
Exam Tip
(-1) (A) में नहीं है, (3) (A) में है और (8) (A) में नहीं है। इसलिए पूरक ([-1,3)\cup[8,\infty)) है।
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