\(यदि (U={1,2,\ldots,30}), (A={x:x\) सम है\(}) और (B={x:x\) अभाज्य है\(}), तो (|A'\cap B'|) कितना है\)?
\(If (U={1,2,\ldots,30}), (A={x:x\) is even\(}) and (B={x:x\) is prime\(}), what is (|A'\cap B'|)\)?
Explanation opens after your attempt
Correct Answer
A. (8)
Concept
(A') is the set of odd numbers and (B') is the set of non-prime numbers. The odd non-primes from (1) to (30) are ({1,9,15,21,25,27}), so the count is (6).
Why this answer is correct
The correct answer is A. (8). (A') is the set of odd numbers and (B') is the set of non-prime numbers. The odd non-primes from (1) to (30) are ({1,9,15,21,25,27}), so the count is (6).
Exam Tip
(A') विषम संख्याएँ हैं और (B') अभाज्य नहीं संख्याएँ हैं। (1) से (30) तक विषम अभाज्य नहीं संख्याएँ ({1,9,15,21,25,27}) नहीं, साथ में (? ) नहीं; सही सूची ({1,9,15,21,25,27}) है, इसलिए संख्या (6) है।
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