\(यदि (U={1,2,\ldots,20}), (A={x:x\) सम है\(}) और (B={x:x\) अभाज्य है\(}), तो (A'\cap B') में कितने अवयव हैं\)?
\(If (U={1,2,\ldots,20}), (A={x:x\) is even\(}) and (B={x:x\) is prime\(}), how many elements are in (A'\cap B')\)?
Explanation opens after your attempt
Correct Answer
B. (6)
Concept
(A') is the set of odd numbers and (B') is the set of non-prime numbers. The correct odd non-primes in (U) are ({1,9,15}), so the count is (3).
Why this answer is correct
The correct answer is B. (6). (A') is the set of odd numbers and (B') is the set of non-prime numbers. The correct odd non-primes in (U) are ({1,9,15}), so the count is (3).
Exam Tip
(A') विषम संख्याएँ हैं और (B') अभाज्य नहीं संख्याएँ हैं। इनमें ({1,9,15,21}) नहीं बल्कि (U) में ({1,9,15}) के साथ ({? }) सोचने की गलती न करें; सही समुच्चय ({1,9,15}) और (? ) नहीं, बल्कि ({1,9,15}) केवल (3) हैं।
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