यदि \(U=\{1,2,3,4,5,6\}\), \(A=\{1,2,3\}\), और \(B=\{3,4,5\}\), तो (n(P\(A'\cup B'\))) क्या है?

If \(U=\{1,2,3,4,5,6\}\), \(A=\{1,2,3\}\), and \(B=\{3,4,5\}\), then what is (n(P\(A'\cup B'\)))?

Explanation opens after your attempt
Correct Answer

C. (32)

Step 1

Concept

(A'\cup B'=\(A\cap B\)'={1,2,4,5,6}), so (n(P\(A'\cup B'\))=25=32). De Morgan's law makes counting easier.

Step 2

Why this answer is correct

The correct answer is C. (32). (A'\cup B'=\(A\cap B\)'={1,2,4,5,6}), so (n(P\(A'\cup B'\))=25=32). De Morgan's law makes counting easier.

Step 3

Exam Tip

(A'\cup B'=\(A\cap B\)'={1,2,4,5,6}), इसलिए (n(P\(A'\cup B'\))=25=32)। डी मॉर्गन नियम से गिनती आसान होती है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U=\{1,2,3,4,5,6\}\), \(A=\{1,2,3\}\), और \(B=\{3,4,5\}\), तो (n(P\(A'\cup B'\))) क्या है? / If \(U=\{1,2,3,4,5,6\}\), \(A=\{1,2,3\}\), and \(B=\{3,4,5\}\), then what is (n(P\(A'\cup B'\)))?

Correct Answer: C. (32). Explanation: (A'\cup B'=\(A\cap B\)'={1,2,4,5,6}), इसलिए (n(P\(A'\cup B'\))=25=32)। डी मॉर्गन नियम से गिनती आसान होती है। / (A'\cup B'=\(A\cap B\)'={1,2,4,5,6}), so (n(P\(A'\cup B'\))=25=32). De Morgan's law makes counting easier.

Which concept should I revise for this Mathematics MCQ?

(A'\cup B'=\(A\cap B\)'={1,2,4,5,6}), so (n(P\(A'\cup B'\))=25=32). De Morgan's law makes counting easier.

What exam hint can help solve this Mathematics question?

(A'\cup B'=\(A\cap B\)'={1,2,4,5,6}), इसलिए (n(P\(A'\cup B'\))=25=32)। डी मॉर्गन नियम से गिनती आसान होती है।