यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\sqrt{x-1}) से परिभाषित करने की कोशिश की जाए, तो यह पूरे \(\mathbb{R}\) पर फलन क्यों नहीं है?
If one tries to define \(f:\mathbb{R}\to\mathbb{R}\) by (f(x)=\sqrt{x-1}), why is it not a function on all of \(\mathbb{R}\)?
Explanation opens after your attempt
A. क्योंकि (x<1) पर \(\sqrt{x-1}\) वास्तविक नहीं हैBecause \(\sqrt{x-1}\) is not real for (x<1)
Concept
The domain is \(\mathbb{R}\), but no real image is obtained for (x<1). In exams, check that the expression inside a square root is not negative.
Why this answer is correct
The correct answer is A. क्योंकि (x<1) पर \(\sqrt{x-1}\) वास्तविक नहीं है / Because \(\sqrt{x-1}\) is not real for (x<1). The domain is \(\mathbb{R}\), but no real image is obtained for (x<1). In exams, check that the expression inside a square root is not negative.
Exam Tip
प्रांत \(\mathbb{R}\) है पर (x<1) के लिए वास्तविक छवि नहीं मिलती। परीक्षा में वर्गमूल के अंदर का मान ऋणात्मक न हो यह जांचें।
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