यदि (n\(A\cup B\)=45), (n(A)=28) और (n(B)=25), तो (n\(A\cap B\)) ज्ञात कीजिए।
If (n\(A\cup B\)=45), (n(A)=28), and (n(B)=25), find (n\(A\cap B\)).
Explanation opens after your attempt
A. (8)
Concept
(n\(A\cap B\)=n(A)+n(B)-n\(A\cup B\)). Therefore (28+25-45=8).
Why this answer is correct
The correct answer is A. (8). (n\(A\cap B\)=n(A)+n(B)-n\(A\cup B\)). Therefore (28+25-45=8).
Exam Tip
(n\(A\cap B\)=n(A)+n(B)-n\(A\cup B\)) है। इसलिए (28+25-45=8)।
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