यदि (n(A-B)=x+4), (n(B-A)=2x-1), (n\(A\cap B\)=x+3) और (n\(A\cup B\)=46) है, तो (x) का मान क्या है?
If (n(A-B)=x+4), (n(B-A)=2x-1), (n\(A\cap B\)=x+3), and (n\(A\cup B\)=46), what is the value of (x)?
Explanation opens after your attempt
A. (10)
Concept
From ((x+4)+(2x-1)+(x+3)=46), (4x+6=46), so (x=10). The sum of disjoint regions is the union.
Why this answer is correct
The correct answer is A. (10). From ((x+4)+(2x-1)+(x+3)=46), (4x+6=46), so (x=10). The sum of disjoint regions is the union.
Exam Tip
((x+4)+(2x-1)+(x+3)=46) से (4x+6=46), इसलिए (x=10)। अलग क्षेत्रों का योग संघ होता है।
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