यदि (n(A-B)=12), (n(B-A)=9) और (n\(A\cap B\)=7), तो (n\(A\cup B\)) क्या है?
If (n(A-B)=12), (n(B-A)=9), and (n\(A\cap B\)=7), what is (n\(A\cup B\))?
Explanation opens after your attempt
A. (28)
Concept
The union is the sum of three disjoint parts (A-B), (B-A), and \(A\cap B\). Thus (12+9+7=28).
Why this answer is correct
The correct answer is A. (28). The union is the sum of three disjoint parts (A-B), (B-A), and \(A\cap B\). Thus (12+9+7=28).
Exam Tip
संघ तीन अलग भागों (A-B), (B-A) और \(A\cap B\) का योग है। इसलिए (12+9+7=28)।
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