यदि (n(A-B)=12), (n(B-A)=9) और (n\(A\cap B\)=7), तो (n\(A\cup B\)) क्या है?

If (n(A-B)=12), (n(B-A)=9), and (n\(A\cap B\)=7), what is (n\(A\cup B\))?

Explanation opens after your attempt
Correct Answer

A. (28)

Step 1

Concept

The union is the sum of three disjoint parts (A-B), (B-A), and \(A\cap B\). Thus (12+9+7=28).

Step 2

Why this answer is correct

The correct answer is A. (28). The union is the sum of three disjoint parts (A-B), (B-A), and \(A\cap B\). Thus (12+9+7=28).

Step 3

Exam Tip

संघ तीन अलग भागों (A-B), (B-A) और \(A\cap B\) का योग है। इसलिए (12+9+7=28)।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A-B)=12), (n(B-A)=9) और (n\(A\cap B\)=7), तो (n\(A\cup B\)) क्या है? / If (n(A-B)=12), (n(B-A)=9), and (n\(A\cap B\)=7), what is (n\(A\cup B\))?

Correct Answer: A. (28). Explanation: संघ तीन अलग भागों (A-B), (B-A) और \(A\cap B\) का योग है। इसलिए (12+9+7=28)। / The union is the sum of three disjoint parts (A-B), (B-A), and \(A\cap B\). Thus (12+9+7=28).

Which concept should I revise for this Mathematics MCQ?

The union is the sum of three disjoint parts (A-B), (B-A), and \(A\cap B\). Thus (12+9+7=28).

What exam hint can help solve this Mathematics question?

संघ तीन अलग भागों (A-B), (B-A) और \(A\cap B\) का योग है। इसलिए (12+9+7=28)।