यदि (n(A)=4x+5), (n(B)=3x+8), (n\(A\cap B\)=2x+1) और (n\(A\cup B\)=72) है, तो (x) का मान क्या होगा?
If (n(A)=4x+5), (n(B)=3x+8), (n\(A\cap B\)=2x+1) and (n\(A\cup B\)=72), then what is the value of (x)?
Explanation opens after your attempt
A. (12)
Concept
Using the formula, (72=(4x+5)+(3x+8)-(2x+1)=5x+12), so (x=12). In algebraic Venn questions, apply the union formula directly.
Why this answer is correct
The correct answer is A. (12). Using the formula, (72=(4x+5)+(3x+8)-(2x+1)=5x+12), so (x=12). In algebraic Venn questions, apply the union formula directly.
Exam Tip
सूत्र से (72=(4x+5)+(3x+8)-(2x+1)=5x+12), इसलिए (x=12) है। बीजगणितीय वेन प्रश्न में संघ का सूत्र सीधे लगाएँ।
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