यदि (n(A)=25), (n(B)=22), (n(C)=19), (n\(A\cap B\)=7), (n\(B\cap C\)=6), (n\(C\cap A\)=5), (n\(A\cap B\cap C\)=2) और (n(U)=60) है, तो किसी भी समुच्चय में नहीं आने वाले कितने हैं?
If (n(A)=25), (n(B)=22), (n(C)=19), (n\(A\cap B\)=7), (n\(B\cap C\)=6), (n\(C\cap A\)=5), (n\(A\cap B\cap C\)=2), and (n(U)=60), how many are in none of the sets?
Explanation opens after your attempt
A. (10)
Concept
The union is (25+22+19-7-6-5+2=50), so none is (60-50=10). In three sets, add back the final common part.
Why this answer is correct
The correct answer is A. (10). The union is (25+22+19-7-6-5+2=50), so none is (60-50=10). In three sets, add back the final common part.
Exam Tip
संघ (25+22+19-7-6-5+2=50) है, इसलिए कोई नहीं (60-50=10)। तीन समुच्चयों में अंतिम साझा भाग वापस जोड़ें।
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