यदि \(\frac{(n+2)!}{(n-2)!}=3024\), तो (n) का मान क्या है?
If \(\frac{(n+2)!}{(n-2)!}=3024 \), what is the value of (n)?
Explanation opens after your attempt
B. (7)
Concept
It is \((n+2)(n+1)n(n-1)=3024\). Since \(9\cdot8\cdot7\cdot6=3024\), (n=7).
Why this answer is correct
The correct answer is B. (7). It is \((n+2)(n+1)n(n-1)=3024\). Since \(9\cdot8\cdot7\cdot6=3024\), (n=7).
Exam Tip
यह \((n+2)(n+1)n(n-1)=3024\) है। \(9\cdot8\cdot7\cdot6=3024\), इसलिए (n=7)।
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