यदि (f(x)=x-2-1) और (g(x)=x-2+1) हैं, तो ((g-f)(x)) का मान किस प्रकार का है?
If (f(x)=x-2-1) and (g(x)=x-2+1), what type of value is ((g-f)(x))?
Explanation opens after your attempt
A. स्थिर धनात्मक (2)Constant positive (2)
Concept
((g-f)(x)=x-2+1-\(x^2-1\)=2). Cancellation of like terms can produce a constant function.
Why this answer is correct
The correct answer is A. स्थिर धनात्मक (2) / Constant positive (2). ((g-f)(x)=x-2+1-\(x^2-1\)=2). Cancellation of like terms can produce a constant function.
Exam Tip
((g-f)(x)=x-2+1-\(x^2-1\)=2)। समान पदों के कटने से स्थिर फलन मिल सकता है।
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