यदि (f(x)=\sqrt{x}) और (g(x)=x-2) हैं, तो \(\frac{f}{g}\) का प्रांत क्या है?

If (f(x)=\sqrt{x}) and (g(x)=x-2), what is the domain of \(\frac{f}{g}\)?

Explanation opens after your attempt
Correct Answer

A. \([0,\infty\)\setminus{2})

Step 1

Concept

\(\sqrt{x}\) needs \(x\ge 0\), and the denominator needs \(x-2\ne 0\). In a quotient, both square-root and denominator restrictions apply.

Step 2

Why this answer is correct

The correct answer is A. \([0,\infty\)\setminus{2}). \(\sqrt{x}\) needs \(x\ge 0\), and the denominator needs \(x-2\ne 0\). In a quotient, both square-root and denominator restrictions apply.

Step 3

Exam Tip

\(\sqrt{x}\) के लिए \(x\ge 0\) और हर \(x-2\ne 0\) चाहिए। भागफल में वर्गमूल और हर दोनों प्रतिबंध लागू होते हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x}) और (g(x)=x-2) हैं, तो \(\frac{f}{g}\) का प्रांत क्या है? / If (f(x)=\sqrt{x}) and (g(x)=x-2), what is the domain of \(\frac{f}{g}\)?

Correct Answer: A. \([0,\infty\)\setminus{2}). Explanation: \(\sqrt{x}\) के लिए \(x\ge 0\) और हर \(x-2\ne 0\) चाहिए। भागफल में वर्गमूल और हर दोनों प्रतिबंध लागू होते हैं। / \(\sqrt{x}\) needs \(x\ge 0\), and the denominator needs \(x-2\ne 0\). In a quotient, both square-root and denominator restrictions apply.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{x}\) needs \(x\ge 0\), and the denominator needs \(x-2\ne 0\). In a quotient, both square-root and denominator restrictions apply.

What exam hint can help solve this Mathematics question?

\(\sqrt{x}\) के लिए \(x\ge 0\) और हर \(x-2\ne 0\) चाहिए। भागफल में वर्गमूल और हर दोनों प्रतिबंध लागू होते हैं।