यदि (f(x)=\sqrt{x}) और (g(x)=\frac{1}{\sqrt{4-x}}) हैं, तो ((fg)(x)) का प्रांत क्या होगा?

If (f(x)=\sqrt{x}) and (g(x)=\frac{1}{\sqrt{4-x}}), what is the domain of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \(0\le x<4\)

Step 1

Concept

For \(\sqrt{x}\), \(x\ge0\), and for denominator \(\sqrt{4-x}\), (4-x>0). Hence \(0\le x<4\).

Step 2

Why this answer is correct

The correct answer is A. \(0\le x<4\). For \(\sqrt{x}\), \(x\ge0\), and for denominator \(\sqrt{4-x}\), (4-x>0). Hence \(0\le x<4\).

Step 3

Exam Tip

\(\sqrt{x}\) के लिए \(x\ge0\) और हर में \(\sqrt{4-x}\) के लिए (4-x>0)। इसलिए \(0\le x<4\)।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x}) और (g(x)=\frac{1}{\sqrt{4-x}}) हैं, तो ((fg)(x)) का प्रांत क्या होगा? / If (f(x)=\sqrt{x}) and (g(x)=\frac{1}{\sqrt{4-x}}), what is the domain of ((fg)(x))?

Correct Answer: A. \(0\le x<4\). Explanation: \(\sqrt{x}\) के लिए \(x\ge0\) और हर में \(\sqrt{4-x}\) के लिए (4-x>0)। इसलिए \(0\le x<4\)। / For \(\sqrt{x}\), \(x\ge0\), and for denominator \(\sqrt{4-x}\), (4-x>0). Hence \(0\le x<4\).

Which concept should I revise for this Mathematics MCQ?

For \(\sqrt{x}\), \(x\ge0\), and for denominator \(\sqrt{4-x}\), (4-x>0). Hence \(0\le x<4\).

What exam hint can help solve this Mathematics question?

\(\sqrt{x}\) के लिए \(x\ge0\) और हर में \(\sqrt{4-x}\) के लिए (4-x>0)। इसलिए \(0\le x<4\)।