यदि (f(x)=\sqrt{x-2-9}) और (g(x)=\frac{1}{x-4}) हैं, तो ((f+g)(x)) का प्रांत क्या होगा?
If (f(x)=\sqrt{x-2-9}) and (g(x)=\frac{1}{x-4}), what is the domain of ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. \(x\le-3\) या \(x\ge3,\ x\ne4\)\(x\le-3\) or \(x\ge3,\ x\ne4\)
Concept
For \(\sqrt{x^2-9}\), \(x^2-9\ge0\), and for the fraction \(x\ne4\). Thus \(x\le-3\) or \(x\ge3\), but (x=4) is removed.
Why this answer is correct
The correct answer is A. \(x\le-3\) या \(x\ge3,\ x\ne4\) / \(x\le-3\) or \(x\ge3,\ x\ne4\). For \(\sqrt{x^2-9}\), \(x^2-9\ge0\), and for the fraction \(x\ne4\). Thus \(x\le-3\) or \(x\ge3\), but (x=4) is removed.
Exam Tip
\(\sqrt{x^2-9}\) के लिए \(x^2-9\ge0\) और भिन्न के लिए \(x\ne4\)। इसलिए \(x\le-3\) या \(x\ge3\), पर (x=4) हटेगा।
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