यदि (f(x)=\sqrt{5-x}) और (g(x)=\sqrt{x+1}) हैं, तो ((fg)(x)) का प्रांत क्या होगा?

If (f(x)=\sqrt{5-x}) and (g(x)=\sqrt{x+1}), what is the domain of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \(-1\le x\le5\)

Step 1

Concept

The domain of a product is the intersection of both domains, so \(5-x\ge0\) and \(x+1\ge0\). Hence \(-1\le x\le5\).

Step 2

Why this answer is correct

The correct answer is A. \(-1\le x\le5\). The domain of a product is the intersection of both domains, so \(5-x\ge0\) and \(x+1\ge0\). Hence \(-1\le x\le5\).

Step 3

Exam Tip

गुणन का प्रांत दोनों प्रांतों का प्रतिच्छेद है, इसलिए \(5-x\ge0\) और \(x+1\ge0\)। अतः \(-1\le x\le5\)।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{5-x}) और (g(x)=\sqrt{x+1}) हैं, तो ((fg)(x)) का प्रांत क्या होगा? / If (f(x)=\sqrt{5-x}) and (g(x)=\sqrt{x+1}), what is the domain of ((fg)(x))?

Correct Answer: A. \(-1\le x\le5\). Explanation: गुणन का प्रांत दोनों प्रांतों का प्रतिच्छेद है, इसलिए \(5-x\ge0\) और \(x+1\ge0\)। अतः \(-1\le x\le5\)। / The domain of a product is the intersection of both domains, so \(5-x\ge0\) and \(x+1\ge0\). Hence \(-1\le x\le5\).

Which concept should I revise for this Mathematics MCQ?

The domain of a product is the intersection of both domains, so \(5-x\ge0\) and \(x+1\ge0\). Hence \(-1\le x\le5\).

What exam hint can help solve this Mathematics question?

गुणन का प्रांत दोनों प्रांतों का प्रतिच्छेद है, इसलिए \(5-x\ge0\) और \(x+1\ge0\)। अतः \(-1\le x\le5\)।