(f) के लिए \(x^2-9\ne 0\), इसलिए \(x\ne \pm3\), और (f(x)) कभी (0) नहीं होता। अतः केवल (-3) और (3) हटेंगे। / For (f), \(x^2-9\ne 0\), so \(x\ne \pm3\), and (f(x)) is never (0). Hence only (-3) and (3) are excluded.
Mathematics Answer, Explanation and Revision Hints
यदि \(f(x)=\frac{1}{x^2-9}\) और \(g(x)=x^2\) हैं, तो \(\left(\frac{g}{f}\right)(x)\) का प्रांत क्या है? / If \(f(x)=\frac{1}{x^2-9}\) and \(g(x)=x^2\), what is the domain of \(\left(\frac{g}{f}\right)(x)\)?
Correct Answer: A. \(\mathbb{R}\setminus{-3,3}\). Explanation: (f) के लिए \(x^2-9\ne 0\), इसलिए \(x\ne \pm3\), और (f(x)) कभी (0) नहीं होता। अतः केवल (-3) और (3) हटेंगे। / For (f), \(x^2-9\ne 0\), so \(x\ne \pm3\), and (f(x)) is never (0). Hence only (-3) and (3) are excluded.
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