यदि (f(x)=\frac{1}{\sqrt{x-2}}) और (g(x)=x-2) हैं, तो ((f+g)(x)) का प्रांत क्या है?
If (f(x)=\frac{1}{\sqrt{x-2}}) and (g(x)=x-2), what is the domain of ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. (\(2,\infty\))
Concept
The denominator has \(\sqrt{x-2}\), so (x-2>0), meaning (x>2). A square root in the denominator cannot be zero.
Why this answer is correct
The correct answer is A. (\(2,\infty\)). The denominator has \(\sqrt{x-2}\), so (x-2>0), meaning (x>2). A square root in the denominator cannot be zero.
Exam Tip
हर में \(\sqrt{x-2}\) है, इसलिए (x-2>0), यानी (x>2)। हर वाले वर्गमूल में शून्य भी निषिद्ध होता है।
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