यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\frac{1}{|x+1|-3}) से दिया जाए, तो सही प्रांत क्या होना चाहिए?
If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\frac{1}{|x+1|-3}), what should be the correct domain?
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}-{-4,2}\)
Concept
The denominator must be non-zero, so \(|x+1|-3\ne0\) and \(|x+1|\ne3\). This gives \(x\ne2,-4\).
Why this answer is correct
The correct answer is A. \(\mathbb{R}-{-4,2}\). The denominator must be non-zero, so \(|x+1|-3\ne0\) and \(|x+1|\ne3\). This gives \(x\ne2,-4\).
Exam Tip
हर शून्य न हो, इसलिए \(|x+1|-3\ne0\) और \(|x+1|\ne3\) चाहिए। इससे \(x\ne2,-4\) मिलता है।
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