यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\frac{1}{|2x-1|-5}) से दिया जाए, तो सही प्रांत क्या होना चाहिए?

If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\frac{1}{|2x-1|-5}), what should be the correct domain?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{-2,3}\)

Step 1

Concept

The denominator must be non-zero, so \(|2x-1|\ne5\). This gives (2x-1=5) or (2x-1=-5), so (x=3,-2) are excluded.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{-2,3}\). The denominator must be non-zero, so \(|2x-1|\ne5\). This gives (2x-1=5) or (2x-1=-5), so (x=3,-2) are excluded.

Step 3

Exam Tip

हर शून्य न हो, इसलिए \(|2x-1|\ne5\) चाहिए। इससे (2x-1=5) या (2x-1=-5), यानी (x=3,-2) हटते हैं।

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यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\frac{1}{|2x-1|-5}) से दिया जाए, तो सही प्रांत क्या होना चाहिए? / If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\frac{1}{|2x-1|-5}), what should be the correct domain?

Correct Answer: A. \(\mathbb{R}-{-2,3}\). Explanation: हर शून्य न हो, इसलिए \(|2x-1|\ne5\) चाहिए। इससे (2x-1=5) या (2x-1=-5), यानी (x=3,-2) हटते हैं। / The denominator must be non-zero, so \(|2x-1|\ne5\). This gives (2x-1=5) or (2x-1=-5), so (x=3,-2) are excluded.

Which concept should I revise for this Mathematics MCQ?

The denominator must be non-zero, so \(|2x-1|\ne5\). This gives (2x-1=5) or (2x-1=-5), so (x=3,-2) are excluded.

What exam hint can help solve this Mathematics question?

हर शून्य न हो, इसलिए \(|2x-1|\ne5\) चाहिए। इससे (2x-1=5) या (2x-1=-5), यानी (x=3,-2) हटते हैं।