यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\begin{cases}4x-5,&x\le2\x+1,&x\ge2\end{cases}) से दिया गया है, तो सही कथन क्या है?
If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\begin{cases}4x-5,&x\le2\x+1,&x\ge2\end{cases}), which statement is correct?
Explanation opens after your attempt
Correct Answer
A. यह फलन है क्योंकि (x=2) पर दोनों नियम (3) देते हैंIt is a function because both rules give (3) at (x=2)
Concept
At (x=2), \(4\cdot2-5=3\) and (2+1=3), so there is no conflict. Overlap is valid when both values agree.
Why this answer is correct
The correct answer is A. यह फलन है क्योंकि (x=2) पर दोनों नियम (3) देते हैं / It is a function because both rules give (3) at (x=2). At (x=2), \(4\cdot2-5=3\) and (2+1=3), so there is no conflict. Overlap is valid when both values agree.
Exam Tip
(x=2) पर \(4\cdot2-5=3\) और (2+1=3) हैं, इसलिए कोई विरोध नहीं है। ओवरलैप तब मान्य है जब दोनों मान समान हों।
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