यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\begin{cases}2x-1,&x\le3\x+2,&x\ge3\end{cases}) से दिया गया है, तो सही कथन क्या है?
If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\begin{cases}2x-1,&x\le3\x+2,&x\ge3\end{cases}), which statement is correct?
Explanation opens after your attempt
Correct Answer
A. यह फलन है क्योंकि (x=3) पर दोनों नियम (5) देते हैंIt is a function because both rules give (5) at (x=3)
Concept
At (x=3), \(2\cdot3-1=5\) and (3+2=5), so there is no conflict. Overlap is valid when both values agree.
Why this answer is correct
The correct answer is A. यह फलन है क्योंकि (x=3) पर दोनों नियम (5) देते हैं / It is a function because both rules give (5) at (x=3). At (x=3), \(2\cdot3-1=5\) and (3+2=5), so there is no conflict. Overlap is valid when both values agree.
Exam Tip
(x=3) पर \(2\cdot3-1=5\) और (3+2=5) हैं, इसलिए कोई विरोध नहीं है। ओवरलैप तब मान्य है जब दोनों मान समान हों।
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