यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\begin{cases}2x+1,&x<2\x-2-1,&x\ge2\end{cases}) से दिया गया है, तो (f(2)) क्या है?
If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\begin{cases}2x+1,&x<2\x-2-1,&x\ge2\end{cases}), what is (f(2))?
Explanation opens after your attempt
A. (3)
Concept
The input (x=2) belongs to the second part, so (f(2)=22-1=3). In piecewise functions, read the boundary sign carefully.
Why this answer is correct
The correct answer is A. (3). The input (x=2) belongs to the second part, so (f(2)=22-1=3). In piecewise functions, read the boundary sign carefully.
Exam Tip
(x=2) दूसरे भाग में आता है, इसलिए (f(2)=22-1=3) है। खंडित फलन में सीमा चिह्न ध्यान से देखें।
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