यदि \(A={x:x\in \mathbb{N},\ x\leq 3}\) और \(B=\{0,1\}\) है, तो \(A\times B\) में कितने तत्व हैं?
If \(A={x:x\in \mathbb{N},\ x\leq 3}\) and \(B=\{0,1\}\), how many elements are in \(A\times B\)?
Explanation opens after your attempt
Correct Answer
C. (6)
Concept
\(A=\{1,2,3\}\) and (B) has (2) elements, so \(3\times 2=6\). First understand the set-builder form.
Why this answer is correct
The correct answer is C. (6). \(A=\{1,2,3\}\) and (B) has (2) elements, so \(3\times 2=6\). First understand the set-builder form.
Exam Tip
\(A=\{1,2,3\}\) और (B) में (2) तत्व हैं, इसलिए \(3\times 2=6\)। पहले सेट-बिल्डर रूप को समझें।
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