यदि \(A={x:x\in \mathbb{N},\ x\leq 2}\) और \(B=\{10,20\}\) है, तो \(A\times B\) में कितने तत्व हैं?
If \(A={x:x\in \mathbb{N},\ x\leq 2}\) and \(B=\{10,20\}\), how many elements are in \(A\times B\)?
Explanation opens after your attempt
Correct Answer
B. (4)
Concept
\(A=\{1,2\}\) and (B) has (2) elements, so \(2\times 2=4\). First convert set-builder form into a list.
Why this answer is correct
The correct answer is B. (4). \(A=\{1,2\}\) and (B) has (2) elements, so \(2\times 2=4\). First convert set-builder form into a list.
Exam Tip
\(A=\{1,2\}\) और (B) में (2) तत्व हैं, इसलिए \(2\times 2=4\)। पहले सेट-बिल्डर रूप को सूची में बदलें।
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