यदि \(A={x:x\in\mathbb{N},x\le2}\) और \(B={y:y\in\mathbb{N},y\le3}\) हैं, तो \(A\times B\) में कितने युग्म होंगे?
If \(A={x:x\in\mathbb{N},x\le2}\) and \(B={y:y\in\mathbb{N},y\le3}\), how many pairs are in \(A\times B\)?
Explanation opens after your attempt
Correct Answer
A. (6)
Concept
\(A=\{1,2\}\) and \(B=\{1,2,3\}\). Hence (n\(A\times B\)=2\times3=6).
Why this answer is correct
The correct answer is A. (6). \(A=\{1,2\}\) and \(B=\{1,2,3\}\). Hence (n\(A\times B\)=2\times3=6).
Exam Tip
\(A=\{1,2\}\) और \(B=\{1,2,3\}\) हैं। अतः (n\(A\times B\)=2\times3=6)।
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