यदि \(A={x\in\mathbb{N}: x\mid 18}\) और \(B={x\in\mathbb{N}: x\mid 24}\), तो \(A\cup B\) क्या है?

If \(A={x\in\mathbb{N}: x\mid 18}\) and \(B={x\in\mathbb{N}: x\mid 24}\), what is \(A\cup B\)?

Explanation opens after your attempt
Correct Answer

A. ({1,2,3,4,6,8,9,12,18,24})

Step 1

Concept

Divisors of (18) are ({1,2,3,6,9,18}), and divisors of (24) are ({1,2,3,4,6,8,12,24}). Combining without repetition gives the union.

Step 2

Why this answer is correct

The correct answer is A. ({1,2,3,4,6,8,9,12,18,24}). Divisors of (18) are ({1,2,3,6,9,18}), and divisors of (24) are ({1,2,3,4,6,8,12,24}). Combining without repetition gives the union.

Step 3

Exam Tip

(18) के भाजक ({1,2,3,6,9,18}) और (24) के भाजक ({1,2,3,4,6,8,12,24}) हैं। दोनों को बिना दोहराव मिलाने पर सही संघ मिलता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(A={x\in\mathbb{N}: x\mid 18}\) और \(B={x\in\mathbb{N}: x\mid 24}\), तो \(A\cup B\) क्या है? / If \(A={x\in\mathbb{N}: x\mid 18}\) and \(B={x\in\mathbb{N}: x\mid 24}\), what is \(A\cup B\)?

Correct Answer: A. ({1,2,3,4,6,8,9,12,18,24}). Explanation: (18) के भाजक ({1,2,3,6,9,18}) और (24) के भाजक ({1,2,3,4,6,8,12,24}) हैं। दोनों को बिना दोहराव मिलाने पर सही संघ मिलता है। / Divisors of (18) are ({1,2,3,6,9,18}), and divisors of (24) are ({1,2,3,4,6,8,12,24}). Combining without repetition gives the union.

Which concept should I revise for this Mathematics MCQ?

Divisors of (18) are ({1,2,3,6,9,18}), and divisors of (24) are ({1,2,3,4,6,8,12,24}). Combining without repetition gives the union.

What exam hint can help solve this Mathematics question?

(18) के भाजक ({1,2,3,6,9,18}) और (24) के भाजक ({1,2,3,4,6,8,12,24}) हैं। दोनों को बिना दोहराव मिलाने पर सही संघ मिलता है।