यदि \(A=\{1,2\}\), \(B=\{2,3\}\) और \(C=\{3,4\}\) हैं, तो (\(A\cup B\)\times C) में कितने अवयव होंगे?

If \(A=\{1,2\}\), \(B=\{2,3\}\) and \(C=\{3,4\}\), how many elements are in (\(A\cup B\)\times C)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

\(A\cup B={1,2,3}\), so (n(\(A\cup B\)\times C)=3\times2=6). Do not count a common element twice.

Step 2

Why this answer is correct

The correct answer is A. (6). \(A\cup B={1,2,3}\), so (n(\(A\cup B\)\times C)=3\times2=6). Do not count a common element twice.

Step 3

Exam Tip

\(A\cup B={1,2,3}\), इसलिए (n(\(A\cup B\)\times C)=3\times2=6)। समान अवयव को दो बार न गिनें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2\}\), \(B=\{2,3\}\) और \(C=\{3,4\}\) हैं, तो (\(A\cup B\)\times C) में कितने अवयव होंगे? / If \(A=\{1,2\}\), \(B=\{2,3\}\) and \(C=\{3,4\}\), how many elements are in (\(A\cup B\)\times C)?

Correct Answer: A. (6). Explanation: \(A\cup B={1,2,3}\), इसलिए (n(\(A\cup B\)\times C)=3\times2=6)। समान अवयव को दो बार न गिनें। / \(A\cup B={1,2,3}\), so (n(\(A\cup B\)\times C)=3\times2=6). Do not count a common element twice.

Which concept should I revise for this Mathematics MCQ?

\(A\cup B={1,2,3}\), so (n(\(A\cup B\)\times C)=3\times2=6). Do not count a common element twice.

What exam hint can help solve this Mathematics question?

\(A\cup B={1,2,3}\), इसलिए (n(\(A\cup B\)\times C)=3\times2=6)। समान अवयव को दो बार न गिनें।