यदि \(A=\{1,2,3\}\), \(B=\{2,3,4\}\) और \(C=\{3,4,5\}\) हैं, तो (A\times(\(B\cup C\)-A)) में कितने अवयव होंगे?
If \(A=\{1,2,3\}\), \(B=\{2,3,4\}\) and \(C=\{3,4,5\}\), how many elements are in (A\times(\(B\cup C\)-A))?
Explanation opens after your attempt
C. (6)
Concept
\(B\cup C={2,3,4,5}\) and (\(B\cup C\)-A={4,5}). Therefore (n(A\times(\(B\cup C\)-A))=3\times2=6).
Why this answer is correct
The correct answer is C. (6). \(B\cup C={2,3,4,5}\) and (\(B\cup C\)-A={4,5}). Therefore (n(A\times(\(B\cup C\)-A))=3\times2=6).
Exam Tip
\(B\cup C={2,3,4,5}\) और (\(B\cup C\)-A={4,5}) है। इसलिए (n(A\times(\(B\cup C\)-A))=3\times2=6)।
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