यदि \(A=\{1,2,3\}\), \(B=\{1,2,3,4\}\) और \(C=\{2,3,5\}\) हैं, तो (|A\times(B-C)|+|\(A\times B\)\cap\(A\times C\)|) क्या है?

If \(A=\{1,2,3\}\), \(B=\{1,2,3,4\}\), and \(C=\{2,3,5\}\), what is (|A\times(B-C)|+|\(A\times B\)\cap\(A\times C\)|)?

Explanation opens after your attempt
Correct Answer

B. (12)

Step 1

Concept

(B-C={1,4}) gives (6) pairs, and \(B\cap C={2,3}\) gives (6) pairs. The sum is (12).

Step 2

Why this answer is correct

The correct answer is B. (12). (B-C={1,4}) gives (6) pairs, and \(B\cap C={2,3}\) gives (6) pairs. The sum is (12).

Step 3

Exam Tip

(B-C={1,4}) से (6) और \(B\cap C={2,3}\) से (6) युग्म मिलते हैं। योग (12) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3\}\), \(B=\{1,2,3,4\}\) और \(C=\{2,3,5\}\) हैं, तो (|A\times(B-C)|+|\(A\times B\)\cap\(A\times C\)|) क्या है? / If \(A=\{1,2,3\}\), \(B=\{1,2,3,4\}\), and \(C=\{2,3,5\}\), what is (|A\times(B-C)|+|\(A\times B\)\cap\(A\times C\)|)?

Correct Answer: B. (12). Explanation: (B-C={1,4}) से (6) और \(B\cap C={2,3}\) से (6) युग्म मिलते हैं। योग (12) है। / (B-C={1,4}) gives (6) pairs, and \(B\cap C={2,3}\) gives (6) pairs. The sum is (12).

Which concept should I revise for this Mathematics MCQ?

(B-C={1,4}) gives (6) pairs, and \(B\cap C={2,3}\) gives (6) pairs. The sum is (12).

What exam hint can help solve this Mathematics question?

(B-C={1,4}) से (6) और \(B\cap C={2,3}\) से (6) युग्म मिलते हैं। योग (12) है।