यदि \(A=\{1,2,3,4,5\}\), \(B=\{2,4\}\) और \(C=\{0,1,2\}\) हैं, तो \((A-B)\times C\) में कितने अवयव होंगे?
If \(A=\{1,2,3,4,5\}\), \(B=\{2,4\}\) and \(C=\{0,1,2\}\), how many elements are there in \((A-B)\times C\)?
Explanation opens after your attempt
Correct Answer
A. (9)
Concept
(A-B={1,3,5}), so (n\((A-B)\times C\)=3\times3=9). First find the set difference and then count the Cartesian product.
Why this answer is correct
The correct answer is A. (9). (A-B={1,3,5}), so (n\((A-B)\times C\)=3\times3=9). First find the set difference and then count the Cartesian product.
Exam Tip
(A-B={1,3,5}), इसलिए (n\((A-B)\times C\)=3\times3=9)। पहले समुच्चय का अंतर निकालें फिर कार्तीय गुणन गिनें।
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