व्यवस्था \(x+2y\le12\), \(2x+y\le12\), \(x+y\ge3\), \(x\ge0\), \(y\ge0\) में कौन सा बिंदु हल क्षेत्र में नहीं है?

For \(x+2y\le12\), \(2x+y\le12\), \(x+y\ge3\), \(x\ge0\), \(y\ge0\), which point is not in the solution region?

Explanation opens after your attempt
Correct Answer

C. ( (1,1) )

Step 1

Concept

At ( (1,1) ), (x+y=2), which is less than (3). In multi-inequality questions, one false condition is enough to reject a point.

Step 2

Why this answer is correct

The correct answer is C. ( (1,1) ). At ( (1,1) ), (x+y=2), which is less than (3). In multi-inequality questions, one false condition is enough to reject a point.

Step 3

Exam Tip

( (1,1) ) पर (x+y=2), जो (3) से कम है। बहु-असमानता प्रश्नों में अस्वीकृति के लिए एक असत्य शर्त काफी है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

व्यवस्था \(x+2y\le12\), \(2x+y\le12\), \(x+y\ge3\), \(x\ge0\), \(y\ge0\) में कौन सा बिंदु हल क्षेत्र में नहीं है? / For \(x+2y\le12\), \(2x+y\le12\), \(x+y\ge3\), \(x\ge0\), \(y\ge0\), which point is not in the solution region?

Correct Answer: C. ( (1,1) ). Explanation: ( (1,1) ) पर (x+y=2), जो (3) से कम है। बहु-असमानता प्रश्नों में अस्वीकृति के लिए एक असत्य शर्त काफी है। / At ( (1,1) ), (x+y=2), which is less than (3). In multi-inequality questions, one false condition is enough to reject a point.

Which concept should I revise for this Mathematics MCQ?

At ( (1,1) ), (x+y=2), which is less than (3). In multi-inequality questions, one false condition is enough to reject a point.

What exam hint can help solve this Mathematics question?

( (1,1) ) पर (x+y=2), जो (3) से कम है। बहु-असमानता प्रश्नों में अस्वीकृति के लिए एक असत्य शर्त काफी है।