तंत्र \(x+y\leq 3\), (2x+2y>8) का ग्राफीय सामान्य क्षेत्र क्या है?
What is the common graphical region of \(x+y\leq 3\), (2x+2y>8)?
Explanation opens after your attempt
B. कोई सामान्य क्षेत्र नहींNo common region
Concept
The second inequality is (x+y>4), which cannot overlap with \(x+y\leq 3\). Exam tip: Simplify proportional boundary lines first.
Why this answer is correct
The correct answer is B. कोई सामान्य क्षेत्र नहीं / No common region. The second inequality is (x+y>4), which cannot overlap with \(x+y\leq 3\). Exam tip: Simplify proportional boundary lines first.
Exam Tip
दूसरी असमानता (x+y>4) है जो \(x+y\leq 3\) से मेल नहीं खाती। परीक्षा सुझाव: समान गुणज वाली रेखाओं को पहले सरल करें।
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