असमानताओं \(x\geq 1\), \(y\geq 0\), \(x+2y\leq 7\), \(2x+y\leq 8\) के हल-क्षेत्र के शीर्ष कौन से हैं?
What are the vertices of the solution region of \(x\geq 1\), \(y\geq 0\), \(x+2y\leq 7\), and \(2x+y\leq 8\)?
Explanation opens after your attempt
C. ((1,0)), ((4,0)), ((3,2)), ((1,3))
Concept
The two slant boundaries meet at ((3,2)). The remaining corners come from valid parts of (x=1) and (y=0).
Why this answer is correct
The correct answer is C. ((1,0)), ((4,0)), ((3,2)), ((1,3)). The two slant boundaries meet at ((3,2)). The remaining corners come from valid parts of (x=1) and (y=0).
Exam Tip
दो तिरछी सीमाएं ((3,2)) पर मिलती हैं। (x=1) और (y=0) की वैध सीमाओं से बाकी कोने मिलते हैं।
Login to save your score, XP, coins and progress.
