असमानताओं \(x\geq 1\), \(y\geq 0\), \(x+2y\leq 7\), \(2x+y\leq 8\) के हल-क्षेत्र के शीर्ष कौन से हैं?

What are the vertices of the solution region of \(x\geq 1\), \(y\geq 0\), \(x+2y\leq 7\), and \(2x+y\leq 8\)?

Explanation opens after your attempt
Correct Answer

C. ((1,0)), ((4,0)), ((3,2)), ((1,3))

Step 1

Concept

The two slant boundaries meet at ((3,2)). The remaining corners come from valid parts of (x=1) and (y=0).

Step 2

Why this answer is correct

The correct answer is C. ((1,0)), ((4,0)), ((3,2)), ((1,3)). The two slant boundaries meet at ((3,2)). The remaining corners come from valid parts of (x=1) and (y=0).

Step 3

Exam Tip

दो तिरछी सीमाएं ((3,2)) पर मिलती हैं। (x=1) और (y=0) की वैध सीमाओं से बाकी कोने मिलते हैं।

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Mathematics Answer, Explanation and Revision Hints

असमानताओं \(x\geq 1\), \(y\geq 0\), \(x+2y\leq 7\), \(2x+y\leq 8\) के हल-क्षेत्र के शीर्ष कौन से हैं? / What are the vertices of the solution region of \(x\geq 1\), \(y\geq 0\), \(x+2y\leq 7\), and \(2x+y\leq 8\)?

Correct Answer: C. ((1,0)), ((4,0)), ((3,2)), ((1,3)). Explanation: दो तिरछी सीमाएं ((3,2)) पर मिलती हैं। (x=1) और (y=0) की वैध सीमाओं से बाकी कोने मिलते हैं। / The two slant boundaries meet at ((3,2)). The remaining corners come from valid parts of (x=1) and (y=0).

Which concept should I revise for this Mathematics MCQ?

The two slant boundaries meet at ((3,2)). The remaining corners come from valid parts of (x=1) and (y=0).

What exam hint can help solve this Mathematics question?

दो तिरछी सीमाएं ((3,2)) पर मिलती हैं। (x=1) और (y=0) की वैध सीमाओं से बाकी कोने मिलते हैं।