असमानताओं \(x\geq 0\), \(y\geq 0\), \(x+2y\leq 10\), \(3x+y\leq 12\) के हल-क्षेत्र के शीर्ष कौन से हैं?
What are the vertices of the solution region of \(x\geq 0\), \(y\geq 0\), \(x+2y\leq 10\), and \(3x+y\leq 12\)?
Explanation opens after your attempt
Correct Answer
A. ((0,0)), ((4,0)), (\left\(\frac{14}{5},\frac{18}{5}\right\)), ((0,5))
Concept
The slant boundaries intersect at (\left\(\frac{14}{5},\frac{18}{5}\right\)). Use valid intercepts on the axes to list all corners.
Why this answer is correct
The correct answer is A. ((0,0)), ((4,0)), (\left\(\frac{14}{5},\frac{18}{5}\right\)), ((0,5)). The slant boundaries intersect at (\left\(\frac{14}{5},\frac{18}{5}\right\)). Use valid intercepts on the axes to list all corners.
Exam Tip
दोनों तिरछी सीमाओं का प्रतिच्छेद (\left\(\frac{14}{5},\frac{18}{5}\right\)) है। अक्षों पर वैध अवरोध लेकर सभी कोने चुनें।
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