Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 51-60 of 609 questions.
How many ways are there to choose (3) pictures from (8) different pictures for an exhibition?
B. (56)
चयन \(\binom{8}{3}=56\) होगा। प्रदर्शनी के लिए चुनना संयोजन है। / The selection is \(\binom{8}{3}=56\). Choosing for an exhibition is a combination.
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How many ways are there to choose (2) digits from (6) digits if order is not considered?
B. (15)
क्रम नहीं देखना है इसलिए \(\binom{6}{2}=15\) है। यही संयोजन और क्रमचय का मुख्य अंतर है। / Order is not considered, so \(\binom{6}{2}=15\). This is the main difference between combination and permutation.
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How many line segments can be formed from (10) points?
B. (45)
एक रेखाखंड के लिए (2) बिंदु चाहिए। इसलिए \(\binom{10}{2}=45\) है। / A line segment needs (2) points. Therefore \(\binom{10}{2}=45\).
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In how many ways can (3) letters be selected from (8) letters if order is not important?
B. (56)
क्रम महत्वपूर्ण नहीं है इसलिए \(\binom{8}{3}=56\) है। चयन वाले प्रश्नों में संयोजन लगाएं। / Order is not important, so \(\binom{8}{3}=56\). Use combinations in selection questions.
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From (5) boys and (5) girls, in how many ways can (1) boy and (1) girl be selected?
C. (25)
तरीके \(\binom{5}{1}\binom{5}{1}=25\) हैं। दोनों चयन स्वतंत्र हैं इसलिए गुणा करें। / The ways are \(\binom{5}{1}\binom{5}{1}=25\). The two selections are independent, so multiply.
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How many ways are there to choose (4) toys from (12) toys?
C. (495)
यह \(\binom{12}{4}=495\) है। बड़े मानों में सूत्र को क्रम से सरल करें। / This is \(\binom{12}{4}=495\). For larger values, simplify the formula step by step.
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In how many ways can at least (1) pencil be selected from (7) colored pencils?
C. (127)
कुल उपसमुच्चय \(2^7\) हैं और खाली चयन हटेगा। इसलिए \(2^7-1=127\) तरीके हैं। / Total subsets are \(2^7\), and the empty selection is removed. Hence the ways are \(2^7-1=127\).
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How many ways are there to select a pair of (2) students from (15) students?
A. (105)
जोड़ी चुनने के तरीके \(\binom{15}{2}=105\) हैं। जोड़ी में क्रम नहीं गिना जाता। / The number of ways is \(\binom{15}{2}=105\). Order is not counted in a pair.
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In how many ways can a team of (6) students be selected from (8) students?
B. (28)
\(\binom{8}{6}=\binom{8}{2}=28\) होता है। अधिक चुनना हो तो न चुने गए लोगों को गिनना आसान होता है। / \(\binom{8}{6}=\binom{8}{2}=28\). When many are selected, counting those not selected is easier.
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In how many ways can a set of (3) books be made from (9) books?
C. (84)
सेट बनाने में क्रम का महत्व नहीं होता। इसलिए \(\binom{9}{3}=84\) सही है। / Order is not important while making a set. Hence \(\binom{9}{3}=84\) is correct.
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