0 reads0 ratings0 helpful
Why is (p) considered even when (p^2) is even in the proof for (\sqrt{2})?
Advertisement
Answer and explanation
Correct answer: Because the square of an odd number is odd
Step 1: If (p) were odd, then (p^2) would also be odd. Step 2: Since (p^2) is even, (p) cannot be odd, so (p) is even. Step 3: This parity fact is very important in the proof.
Frequently asked questions
What is the correct answer to this question?
Because the square of an odd number is odd
Why is this the correct answer?
Step 1: If (p) were odd, then (p^2) would also be odd. Step 2: Since (p^2) is even, (p) cannot be odd, so (p) is even. Step 3: This parity fact is very important in the proof.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement