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Which statement starts the proof of irrationality of (\sqrt{5}) most clearly?

Answer and explanation

Correct answer: Assume (\sqrt{5}=\frac{a}{b}), where (a,b) are coprime integers and (b\neq0)

Step 1: For contradiction, first assume (\sqrt{5}) is rational. Step 2: Write the rational form as a lowest-form fraction with (b\neq0). Step 3: This start makes the later contradiction strong.

Related tags

Real-NumbersRoot5Opening-StatementRational-FormProof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real NumbersMathematics

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