भिन्न \(\frac{91}{2^3\cdot5^2\cdot13}\) के दशमलव प्रसार के बारे में सही कथन कौन सा है?

Which statement is correct about the decimal expansion of \(\frac{91}{2^3\cdot5^2\cdot13}\)?

Explanation opens after your attempt
Correct Answer

B. यह अनवसानी आवर्ती दशमलव हैIt is non-terminating recurring decimal

Step 1

Concept

The denominator contains (13), and after simplification the denominator is not made only of (2) and (5). In exams always check prime factors of the denominator.

Step 2

Why this answer is correct

The correct answer is B. यह अनवसानी आवर्ती दशमलव है / It is non-terminating recurring decimal. The denominator contains (13), and after simplification the denominator is not made only of (2) and (5). In exams always check prime factors of the denominator.

Step 3

Exam Tip

हर में (13) है और भिन्न सरल करने पर भी केवल (2) और (5) नहीं बचते। परीक्षा में हर के अभाज्य गुणनखंड जरूर जांचें।

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भिन्न \(\frac{91}{2^3\cdot5^2\cdot13}\) के दशमलव प्रसार के बारे में सही कथन कौन सा है? / Which statement is correct about the decimal expansion of \(\frac{91}{2^3\cdot5^2\cdot13}\)?

Correct Answer: B. यह अनवसानी आवर्ती दशमलव है / It is non-terminating recurring decimal. Explanation: हर में (13) है और भिन्न सरल करने पर भी केवल (2) और (5) नहीं बचते। परीक्षा में हर के अभाज्य गुणनखंड जरूर जांचें। / The denominator contains (13), and after simplification the denominator is not made only of (2) and (5). In exams always check prime factors of the denominator.

Which concept should I revise for this Mathematics MCQ?

The denominator contains (13), and after simplification the denominator is not made only of (2) and (5). In exams always check prime factors of the denominator.

What exam hint can help solve this Mathematics question?

हर में (13) है और भिन्न सरल करने पर भी केवल (2) और (5) नहीं बचते। परीक्षा में हर के अभाज्य गुणनखंड जरूर जांचें।