Which of the following statements is true for the polynomial \(p(x)=x^2+4x+4\)?
Answer and explanation
Correct answer: \(p(-2)=0\)
Substituting \(x=-2\) gives \(p(-2)=(-2)^2+4(-2)+4=4-8+4=0\). Therefore, \(-2\) is a zero of the polynomial. Option B is incorrect because \(p(0)=4\); similarly, \(p(2)=16\) and \(p(4)=36\). Exam tip: To test whether a number is a zero, substitute it into the polynomial and check whether the result is \(0\).
Frequently asked questions
What is the correct answer to this question?
\(p(-2)=0\)
Why is this the correct answer?
Substituting \(x=-2\) gives \(p(-2)=(-2)^2+4(-2)+4=4-8+4=0\). Therefore, \(-2\) is a zero of the polynomial. Option B is incorrect because \(p(0)=4\); similarly, \(p(2)=16\) and \(p(4)=36\). Exam tip: To test whether a number is a zero, substitute it into the polynomial and check whether the result is \(0\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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