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If p(x) = x^4 - 2x^2 + 1, what is the value of p(-1)?
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Substituting -1 for x gives p(-1) = (-1)^4 - 2(-1)^2 + 1 = 1 - 2 + 1 = 0. Since even powers of -1 equal 1, treating x^2 as -1 would incorrectly give -2. Exam tip: Always enclose a negative value in brackets before raising it to a power.
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Why is this the correct answer?
Substituting -1 for x gives p(-1) = (-1)^4 - 2(-1)^2 + 1 = 1 - 2 + 1 = 0. Since even powers of -1 equal 1, treating x^2 as -1 would incorrectly give -2. Exam tip: Always enclose a negative value in brackets before raising it to a power.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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